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py/lexer: Raise SyntaxError when str hex escape sequence is malformed. 

Addresses issue #1390.
modjni
Damien George 2015-07-23 23:20:37 +01:00
parent f17e663493
commit d241c2a592
2 changed files with 20 additions and 2 deletions
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4
py/lexer.c
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@ -454,8 +454,8 @@ STATIC void mp_lexer_next_token_into(mp_lexer_t *lex, bool first_token) {
{
mp_uint_t num = 0;
if (!get_hex(lex, (c == 'x' ? 2 : c == 'u' ? 4 : 8), &num)) {
// TODO error message
assert(0);
// not enough hex chars for escape sequence
lex->tok_kind = MP_TOKEN_INVALID;
}
c = num;
break;

18
tests/basics/lexer.py
View File

@ -38,3 +38,21 @@ def a(x):
if x:
print(x)
a(1)
# badly formed hex escape sequences
try:
exec(r"'\x0'")
except SyntaxError:
print("SyntaxError")
try:
exec(r"b'\x0'")
except SyntaxError:
print("SyntaxError")
try:
exec(r"'\u000'")
except SyntaxError:
print("SyntaxError")
try:
exec(r"'\U0000000'")
except SyntaxError:
print("SyntaxError")