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py: Implement divmod for mpz bignum.

modjni
Damien George 2015-06-13 22:40:50 +01:00
parent c5029bcbf3
commit e9ce00d874
2 changed files with 17 additions and 0 deletions
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11
py/objint_mpz.c
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@ -262,6 +262,17 @@ mp_obj_t mp_obj_int_binary_op(mp_uint_t op, mp_obj_t lhs_in, mp_obj_t rhs_in) {
mpz_pow_inpl(&res->mpz, zlhs, zrhs);
break;
case MP_BINARY_OP_DIVMOD: {
mp_obj_int_t *quo = mp_obj_int_new_mpz();
mpz_divmod_inpl(&quo->mpz, &res->mpz, zlhs, zrhs);
// Check signs and do Python style modulo
if (zlhs->neg != zrhs->neg) {
mpz_add_inpl(&res->mpz, &res->mpz, zrhs);
}
mp_obj_t tuple[2] = {quo, res};
return mp_obj_new_tuple(2, tuple);
}
default:
return MP_OBJ_NULL; // op not supported
}

6
tests/basics/builtin_divmod.py
View File

@ -14,3 +14,9 @@ try:
except TypeError:
print("TypeError")
# bignum
l = (1 << 65) + 123
print(divmod(3, l))
print(divmod(l, 5))
print(divmod(l + 3, l))
print(divmod(l * 20, l + 2))