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Fix roundup_pow_of_two(1) 

1 is a power of two, therefore roundup_pow_of_two(1) should return 1. It does
in case the argument is a variable but in case it's a constant it behaves
wrong and returns 0. Probably nobody ever did it so this was never noticed.

Signed-off-by: Rolf Eike Beer <eike-kernel@sf-tec.de>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
hifive-unleashed-5.1
Rolf Eike Beer 2007-05-17 23:56:56 +02:00 committed by Linus Torvalds
parent 18963c01b8
commit 1a06a52ee1
1 changed files with 1 additions and 1 deletions
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2
include/linux/log2.h
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@ -159,7 +159,7 @@ unsigned long __roundup_pow_of_two(unsigned long n)
#define roundup_pow_of_two(n) \
( \
__builtin_constant_p(n) ? ( \
(n == 1) ? 0 : \
(n == 1) ? 1 : \
(1UL << (ilog2((n) - 1) + 1)) \
) : \
__roundup_pow_of_two(n) \