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sched/core: Remove ttwu_activate() 

After the removal of try_to_wake_up_local(), there is only one user of
ttwu_activate() left, and since it is a trivial function, remove it.

Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Signed-off-by: Ingo Molnar <mingo@kernel.org>
hifive-unleashed-5.2
Peter Zijlstra 2019-04-09 09:53:13 +02:00 committed by Ingo Molnar
parent 6d25be5782
commit 1b174a2cb6
1 changed files with 2 additions and 7 deletions
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9
kernel/sched/core.c
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@ -1681,12 +1681,6 @@ ttwu_stat(struct task_struct *p, int cpu, int wake_flags)
__schedstat_inc(p->se.statistics.nr_wakeups_sync);
}
static inline void ttwu_activate(struct rq *rq, struct task_struct *p, int en_flags)
{
activate_task(rq, p, en_flags);
p->on_rq = TASK_ON_RQ_QUEUED;
}
/*
* Mark the task runnable and perform wakeup-preemption.
*/
@ -1738,7 +1732,8 @@ ttwu_do_activate(struct rq *rq, struct task_struct *p, int wake_flags,
en_flags |= ENQUEUE_MIGRATED;
#endif
ttwu_activate(rq, p, en_flags);
activate_task(rq, p, en_flags);
p->on_rq = TASK_ON_RQ_QUEUED;
ttwu_do_wakeup(rq, p, wake_flags, rf);
}