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Fix "check_slabp" printout size calculation 

We want to use the "struct slab" size, not the size of the pointer to
same.  As it is, we'd not print out the last <n> entry pointers in the
slab (where <n> is ~10, depending on whether it's a 32-bit or 64-bit
kernel).

Gaah, that slab code was written by somebody who likes unreadable crud.

Signed-off-by: Linus Torvalds <torvalds@osdl.org>
hifive-unleashed-5.1
Linus Torvalds 2006-03-06 12:10:07 -08:00
parent 24ed6e2c78
commit 264132bc62
1 changed files with 1 additions and 1 deletions
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2
mm/slab.c
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@ -2554,7 +2554,7 @@ static void check_slabp(struct kmem_cache *cachep, struct slab *slabp)
"slab: Internal list corruption detected in cache '%s'(%d), slabp %p(%d). Hexdump:\n",
cachep->name, cachep->num, slabp, slabp->inuse);
for (i = 0;
i < sizeof(slabp) + cachep->num * sizeof(kmem_bufctl_t);
i < sizeof(*slabp) + cachep->num * sizeof(kmem_bufctl_t);
i++) {
if ((i % 16) == 0)
printk("\n%03x:", i);