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kconfig: update current_pos in the second lexer

To simplify the generated lexer, let the hand-made lexer update the
file name and line number for the parser.

I tested this with DEBUG_PARSE, and confirmed the same file names
and line numbers were dumped.

Signed-off-by: Masahiro Yamada <yamada.masahiro@socionext.com>
hifive-unleashed-5.1
Masahiro Yamada 2018-12-11 20:01:09 +09:00
parent 824fa3b3b5
commit 4b31a32caf
1 changed files with 15 additions and 5 deletions

View File

@ -101,8 +101,6 @@ n [A-Za-z0-9_-]
<COMMAND>{
{n}+ {
const struct kconf_id *id = kconf_id_lookup(yytext, yyleng);
current_pos.file = current_file;
current_pos.lineno = yylineno;
if (id && id->flags & TF_COMMAND) {
BEGIN(PARAM);
return id->token;
@ -285,9 +283,21 @@ int yylex(void)
repeat:
token = yylex1();
/* Do not pass unneeded T_EOL to the parser. */
if ((prev_token == T_EOL || prev_token == T_HELPTEXT) && token == T_EOL)
goto repeat;
if (prev_token == T_EOL || prev_token == T_HELPTEXT) {
if (token == T_EOL) {
/* Do not pass unneeded T_EOL to the parser. */
goto repeat;
} else {
/*
* For the parser, update file/lineno at the first token
* of each statement. Generally, \n is a statement
* terminator in Kconfig, but it is not always true
* because \n could be escaped by a backslash.
*/
current_pos.file = current_file;
current_pos.lineno = yylineno;
}
}
if (prev_prev_token == T_EOL && prev_token == T_WORD &&
(token == T_EQUAL || token == T_COLON_EQUAL || token == T_PLUS_EQUAL))