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x86/debug/32: Convert a smp_processor_id() call to raw to avoid DEBUG_PREEMPT warning

... to raw_smp_processor_id() to not trip the

  BUG: using smp_processor_id() in preemptible [00000000] code: swapper/0/1

check. The reasoning behind it is that __warn() already uses the raw_
variants but the show_regs() path on 32-bit doesn't.

Signed-off-by: Borislav Petkov <bp@suse.de>
Cc: Josh Poimboeuf <jpoimboe@redhat.com>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Link: http://lkml.kernel.org/r/20170528092212.fiod7kygpjm23m3o@pd.tnic
Signed-off-by: Ingo Molnar <mingo@kernel.org>
hifive-unleashed-5.1
Borislav Petkov 2017-05-28 11:03:42 +02:00 committed by Ingo Molnar
parent dac6ca243c
commit 5d9070b1f0
1 changed files with 1 additions and 1 deletions

View File

@ -78,7 +78,7 @@ void __show_regs(struct pt_regs *regs, int all)
printk(KERN_DEFAULT "EIP: %pS\n", (void *)regs->ip);
printk(KERN_DEFAULT "EFLAGS: %08lx CPU: %d\n", regs->flags,
smp_processor_id());
raw_smp_processor_id());
printk(KERN_DEFAULT "EAX: %08lx EBX: %08lx ECX: %08lx EDX: %08lx\n",
regs->ax, regs->bx, regs->cx, regs->dx);