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crypto: wait for a full jiffy in do_xor_speed 

In the existing do_xor_speed(), there is no guarantee that we actually
run do_2() for a full jiffy. We get the current jiffy, then run do_2()
until the next jiffy.

Instead, let's get the current jiffy, then wait until the next jiffy
to start our test.

Signed-off-by: Jim Kukunas <james.t.kukunas@linux.intel.com>
Signed-off-by: NeilBrown <neilb@suse.de>
hifive-unleashed-5.1
Jim Kukunas 2012-05-22 13:54:03 +10:00 committed by NeilBrown
parent 3ea7daa5d7
commit 6a328475cc
1 changed files with 5 additions and 3 deletions
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8
crypto/xor.c
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@ -63,7 +63,7 @@ static void
do_xor_speed(struct xor_block_template *tmpl, void *b1, void *b2)
{
int speed;
unsigned long now;
unsigned long now, j;
int i, count, max;
tmpl->next = template_list;
@ -76,9 +76,11 @@ do_xor_speed(struct xor_block_template *tmpl, void *b1, void *b2)
*/
max = 0;
for (i = 0; i < 5; i++) {
now = jiffies;
j = jiffies;
count = 0;
while (jiffies == now) {
while ((now = jiffies) == j)
cpu_relax();
while (time_before(jiffies, now + 1)) {
mb(); /* prevent loop optimzation */
tmpl->do_2(BENCH_SIZE, b1, b2);
mb();