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habanalabs: correctly cast variable to __le32 

When using the macro le32_to_cpu(x), we need to correctly convert x to be
__le32 in case it is defined as u32 variable.

Signed-off-by: Oded Gabbay <oded.gabbay@gmail.com>
Reviewed-by: Tomer Tayar <ttayar@habana.ai>
alistair/sunxi64-5.4-dsi
Oded Gabbay 2019-09-03 11:33:55 +03:00
parent 307eae93d5
commit 6dc66f7c26
1 changed files with 2 additions and 2 deletions
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4
drivers/misc/habanalabs/habanalabs.h
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@ -1107,13 +1107,13 @@ void hl_wreg(struct hl_device *hdev, u32 reg, u32 val);
mb(); \
(val) = *((u32 *) (uintptr_t) (addr)); \
if (mem_written_by_device) \
(val) = le32_to_cpu(val); \
(val) = le32_to_cpu(*(__le32 *) &(val)); \
if (cond) \
break; \
if (timeout_us && ktime_compare(ktime_get(), __timeout) > 0) { \
(val) = *((u32 *) (uintptr_t) (addr)); \
if (mem_written_by_device) \
(val) = le32_to_cpu(val); \
(val) = le32_to_cpu(*(__le32 *) &(val)); \
break; \
} \
if (sleep_us) \