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imx-drm: ipu-dp: Introduce IPUV3_NUM_FLOWS

IPUv3 has a total of 3 flows (one synchronous flow and 2 asynchronous flows).

Let's add a definition for such number in order to let the code easier to
understand.

Signed-off-by: Fabio Estevam <fabio.estevam@freescale.com>
Acked-by: Sascha Hauer <s.hauer@pengutronix.de>
Acked-by: Philipp Zabel <p.zabel@pengutronix.de>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
hifive-unleashed-5.1
Fabio Estevam 2013-06-28 13:55:30 -03:00 committed by Greg Kroah-Hartman
parent ded15b5af1
commit 6fe9a899ed
1 changed files with 5 additions and 3 deletions

View File

@ -46,6 +46,8 @@
#define DP_COM_CONF_CSC_DEF_BG (2 << 8)
#define DP_COM_CONF_CSC_DEF_BOTH (1 << 8)
#define IPUV3_NUM_FLOWS 3
struct ipu_dp_priv;
struct ipu_dp {
@ -67,7 +69,7 @@ struct ipu_dp_priv {
struct ipu_soc *ipu;
struct device *dev;
void __iomem *base;
struct ipu_flow flow[3];
struct ipu_flow flow[IPUV3_NUM_FLOWS];
struct mutex mutex;
int use_count;
};
@ -280,7 +282,7 @@ struct ipu_dp *ipu_dp_get(struct ipu_soc *ipu, unsigned int flow)
struct ipu_dp_priv *priv = ipu->dp_priv;
struct ipu_dp *dp;
if (flow > 5)
if ((flow >> 1) >= IPUV3_NUM_FLOWS)
return ERR_PTR(-EINVAL);
if (flow & 1)
@ -322,7 +324,7 @@ int ipu_dp_init(struct ipu_soc *ipu, struct device *dev, unsigned long base)
mutex_init(&priv->mutex);
for (i = 0; i < 3; i++) {
for (i = 0; i < IPUV3_NUM_FLOWS; i++) {
priv->flow[i].foreground.foreground = 1;
priv->flow[i].base = priv->base + ipu_dp_flow_base[i];
priv->flow[i].priv = priv;