diff --git a/block/bfq-iosched.c b/block/bfq-iosched.c index 44c6bbcd7720..9bc10198ddff 100644 --- a/block/bfq-iosched.c +++ b/block/bfq-iosched.c @@ -1735,6 +1735,72 @@ static void bfq_bfqq_handle_idle_busy_switch(struct bfq_data *bfqd, false, BFQQE_PREEMPTED); } +static void bfq_reset_inject_limit(struct bfq_data *bfqd, + struct bfq_queue *bfqq) +{ + /* invalidate baseline total service time */ + bfqq->last_serv_time_ns = 0; + + /* + * Reset pointer in case we are waiting for + * some request completion. + */ + bfqd->waited_rq = NULL; + + /* + * If bfqq has a short think time, then start by setting the + * inject limit to 0 prudentially, because the service time of + * an injected I/O request may be higher than the think time + * of bfqq, and therefore, if one request was injected when + * bfqq remains empty, this injected request might delay the + * service of the next I/O request for bfqq significantly. In + * case bfqq can actually tolerate some injection, then the + * adaptive update will however raise the limit soon. This + * lucky circumstance holds exactly because bfqq has a short + * think time, and thus, after remaining empty, is likely to + * get new I/O enqueued---and then completed---before being + * expired. This is the very pattern that gives the + * limit-update algorithm the chance to measure the effect of + * injection on request service times, and then to update the + * limit accordingly. + * + * However, in the following special case, the inject limit is + * left to 1 even if the think time is short: bfqq's I/O is + * synchronized with that of some other queue, i.e., bfqq may + * receive new I/O only after the I/O of the other queue is + * completed. Keeping the inject limit to 1 allows the + * blocking I/O to be served while bfqq is in service. And + * this is very convenient both for bfqq and for overall + * throughput, as explained in detail in the comments in + * bfq_update_has_short_ttime(). + * + * On the opposite end, if bfqq has a long think time, then + * start directly by 1, because: + * a) on the bright side, keeping at most one request in + * service in the drive is unlikely to cause any harm to the + * latency of bfqq's requests, as the service time of a single + * request is likely to be lower than the think time of bfqq; + * b) on the downside, after becoming empty, bfqq is likely to + * expire before getting its next request. With this request + * arrival pattern, it is very hard to sample total service + * times and update the inject limit accordingly (see comments + * on bfq_update_inject_limit()). So the limit is likely to be + * never, or at least seldom, updated. As a consequence, by + * setting the limit to 1, we avoid that no injection ever + * occurs with bfqq. On the downside, this proactive step + * further reduces chances to actually compute the baseline + * total service time. Thus it reduces chances to execute the + * limit-update algorithm and possibly raise the limit to more + * than 1. + */ + if (bfq_bfqq_has_short_ttime(bfqq)) + bfqq->inject_limit = 0; + else + bfqq->inject_limit = 1; + + bfqq->decrease_time_jif = jiffies; +} + static void bfq_add_request(struct request *rq) { struct bfq_queue *bfqq = RQ_BFQQ(rq); @@ -1755,71 +1821,8 @@ static void bfq_add_request(struct request *rq) * bfq_update_inject_limit(). */ if (time_is_before_eq_jiffies(bfqq->decrease_time_jif + - msecs_to_jiffies(1000))) { - /* invalidate baseline total service time */ - bfqq->last_serv_time_ns = 0; - - /* - * Reset pointer in case we are waiting for - * some request completion. - */ - bfqd->waited_rq = NULL; - - /* - * If bfqq has a short think time, then start - * by setting the inject limit to 0 - * prudentially, because the service time of - * an injected I/O request may be higher than - * the think time of bfqq, and therefore, if - * one request was injected when bfqq remains - * empty, this injected request might delay - * the service of the next I/O request for - * bfqq significantly. In case bfqq can - * actually tolerate some injection, then the - * adaptive update will however raise the - * limit soon. This lucky circumstance holds - * exactly because bfqq has a short think - * time, and thus, after remaining empty, is - * likely to get new I/O enqueued---and then - * completed---before being expired. This is - * the very pattern that gives the - * limit-update algorithm the chance to - * measure the effect of injection on request - * service times, and then to update the limit - * accordingly. - * - * On the opposite end, if bfqq has a long - * think time, then start directly by 1, - * because: - * a) on the bright side, keeping at most one - * request in service in the drive is unlikely - * to cause any harm to the latency of bfqq's - * requests, as the service time of a single - * request is likely to be lower than the - * think time of bfqq; - * b) on the downside, after becoming empty, - * bfqq is likely to expire before getting its - * next request. With this request arrival - * pattern, it is very hard to sample total - * service times and update the inject limit - * accordingly (see comments on - * bfq_update_inject_limit()). So the limit is - * likely to be never, or at least seldom, - * updated. As a consequence, by setting the - * limit to 1, we avoid that no injection ever - * occurs with bfqq. On the downside, this - * proactive step further reduces chances to - * actually compute the baseline total service - * time. Thus it reduces chances to execute the - * limit-update algorithm and possibly raise the - * limit to more than 1. - */ - if (bfq_bfqq_has_short_ttime(bfqq)) - bfqq->inject_limit = 0; - else - bfqq->inject_limit = 1; - bfqq->decrease_time_jif = jiffies; - } + msecs_to_jiffies(1000))) + bfq_reset_inject_limit(bfqd, bfqq); /* * The following conditions must hold to setup a new @@ -4855,7 +4858,7 @@ static void bfq_update_has_short_ttime(struct bfq_data *bfqd, struct bfq_queue *bfqq, struct bfq_io_cq *bic) { - bool has_short_ttime = true; + bool has_short_ttime = true, state_changed; /* * No need to update has_short_ttime if bfqq is async or in @@ -4880,13 +4883,93 @@ static void bfq_update_has_short_ttime(struct bfq_data *bfqd, bfqq->ttime.ttime_mean > bfqd->bfq_slice_idle)) has_short_ttime = false; - bfq_log_bfqq(bfqd, bfqq, "update_has_short_ttime: has_short_ttime %d", - has_short_ttime); + state_changed = has_short_ttime != bfq_bfqq_has_short_ttime(bfqq); if (has_short_ttime) bfq_mark_bfqq_has_short_ttime(bfqq); else bfq_clear_bfqq_has_short_ttime(bfqq); + + /* + * Until the base value for the total service time gets + * finally computed for bfqq, the inject limit does depend on + * the think-time state (short|long). In particular, the limit + * is 0 or 1 if the think time is deemed, respectively, as + * short or long (details in the comments in + * bfq_update_inject_limit()). Accordingly, the next + * instructions reset the inject limit if the think-time state + * has changed and the above base value is still to be + * computed. + * + * However, the reset is performed only if more than 100 ms + * have elapsed since the last update of the inject limit, or + * (inclusive) if the change is from short to long think + * time. The reason for this waiting is as follows. + * + * bfqq may have a long think time because of a + * synchronization with some other queue, i.e., because the + * I/O of some other queue may need to be completed for bfqq + * to receive new I/O. This happens, e.g., if bfqq is + * associated with a process that does some sync. A sync + * generates extra blocking I/O, which must be completed + * before the process associated with bfqq can go on with its + * I/O. + * + * If such a synchronization is actually in place, then, + * without injection on bfqq, the blocking I/O cannot happen + * to served while bfqq is in service. As a consequence, if + * bfqq is granted I/O-dispatch-plugging, then bfqq remains + * empty, and no I/O is dispatched, until the idle timeout + * fires. This is likely to result in lower bandwidth and + * higher latencies for bfqq, and in a severe loss of total + * throughput. + * + * On the opposite end, a non-zero inject limit may allow the + * I/O that blocks bfqq to be executed soon, and therefore + * bfqq to receive new I/O soon. But, if this actually + * happens, then the next think-time sample for bfqq may be + * very low. This in turn may cause bfqq's think time to be + * deemed short. Without the 100 ms barrier, this new state + * change would cause the body of the next if to be executed + * immediately. But this would set to 0 the inject + * limit. Without injection, the blocking I/O would cause the + * think time of bfqq to become long again, and therefore the + * inject limit to be raised again, and so on. The only effect + * of such a steady oscillation between the two think-time + * states would be to prevent effective injection on bfqq. + * + * In contrast, if the inject limit is not reset during such a + * long time interval as 100 ms, then the number of short + * think time samples can grow significantly before the reset + * is allowed. As a consequence, the think time state can + * become stable before the reset. There will be no state + * change when the 100 ms elapse, and therefore no reset of + * the inject limit. The inject limit remains steadily equal + * to 1 both during and after the 100 ms. So injection can be + * performed at all times, and throughput gets boosted. + * + * An inject limit equal to 1 is however in conflict, in + * general, with the fact that the think time of bfqq is + * short, because injection may be likely to delay bfqq's I/O + * (as explained in the comments in + * bfq_update_inject_limit()). But this does not happen in + * this special case, because bfqq's low think time is due to + * an effective handling of a synchronization, through + * injection. In this special case, bfqq's I/O does not get + * delayed by injection; on the contrary, bfqq's I/O is + * brought forward, because it is not blocked for + * milliseconds. + * + * In addition, during the 100 ms, the base value for the + * total service time is likely to get finally computed, + * freeing the inject limit from its relation with the think + * time. + */ + if (state_changed && bfqq->last_serv_time_ns == 0 && + (time_is_before_eq_jiffies(bfqq->decrease_time_jif + + msecs_to_jiffies(100)) || + !has_short_ttime)) + bfq_reset_inject_limit(bfqd, bfqq); } /*