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Btrfs: fix unprotected assignment of the left cursor for device replace 

We were assigning new values to fields of the device replace object
without holding the respective lock after processing each device extent.
This is important for the left cursor field which can be accessed by a
concurrent task running __btrfs_map_block (which, correctly, takes the
device replace lock).
So change these fields while holding the device replace lock.

Signed-off-by: Filipe Manana <fdmanana@suse.com>
Reviewed-by: Josef Bacik <jbacik@fb.com>
hifive-unleashed-5.1
Filipe Manana 2016-05-14 16:32:35 +01:00
parent f0e9b7d640
commit 81e87a736c
1 changed files with 4 additions and 0 deletions
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4
fs/btrfs/scrub.c
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@ -3642,9 +3642,11 @@ int scrub_enumerate_chunks(struct scrub_ctx *sctx,
break;
}
btrfs_dev_replace_lock(&fs_info->dev_replace, 1);
dev_replace->cursor_right = found_key.offset + length;
dev_replace->cursor_left = found_key.offset;
dev_replace->item_needs_writeback = 1;
btrfs_dev_replace_unlock(&fs_info->dev_replace, 1);
ret = scrub_chunk(sctx, scrub_dev, chunk_offset, length,
found_key.offset, cache, is_dev_replace);
@ -3718,8 +3720,10 @@ int scrub_enumerate_chunks(struct scrub_ctx *sctx,
break;
}
btrfs_dev_replace_lock(&fs_info->dev_replace, 1);
dev_replace->cursor_left = dev_replace->cursor_right;
dev_replace->item_needs_writeback = 1;
btrfs_dev_replace_unlock(&fs_info->dev_replace, 1);
skip:
key.offset = found_key.offset + length;
btrfs_release_path(path);