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iocost: check active_list of all the ancestors in iocg_activate() 

There is a bug that checking the same active_list over and over again
in iocg_activate(). The intention of the code was checking whether all
the ancestors and self have already been activated. So fix it.

Fixes: 7caa47151a ("blkcg: implement blk-iocost")
Acked-by: Tejun Heo <tj@kernel.org>
Signed-off-by: Jiufei Xue <jiufei.xue@linux.alibaba.com>
Signed-off-by: Jens Axboe <axboe@kernel.dk>
alistair/sunxi64-5.4-dsi
Jiufei Xue 2019-11-13 15:21:31 +08:00 committed by Jens Axboe
parent 478de3380c
commit 8b37bc277f
1 changed files with 6 additions and 2 deletions
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8
block/blk-iocost.c
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@ -1057,9 +1057,12 @@ static bool iocg_activate(struct ioc_gq *iocg, struct ioc_now *now)
atomic64_set(&iocg->active_period, cur_period);
/* already activated or breaking leaf-only constraint? */
for (i = iocg->level; i > 0; i--)
if (!list_empty(&iocg->active_list))
if (!list_empty(&iocg->active_list))
goto succeed_unlock;
for (i = iocg->level - 1; i > 0; i--)
if (!list_empty(&iocg->ancestors[i]->active_list))
goto fail_unlock;
if (iocg->child_active_sum)
goto fail_unlock;
@ -1101,6 +1104,7 @@ static bool iocg_activate(struct ioc_gq *iocg, struct ioc_now *now)
ioc_start_period(ioc, now);
}
succeed_unlock:
spin_unlock_irq(&ioc->lock);
return true;