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sctp: only drop the reference on the datamsg after sending a msg 

If the chunks are enqueued successfully but sctp_cmd_interpreter()
return err to sctp_sendmsg() (mainly because of no mem), the chunks will
get re-queued, but we are dropping the reference and freeing them.

The fix is to just drop the reference on the datamsg just as it had
succeeded, as:
 - if the chunks weren't queued, this is enough to get them freed.
 - if they were queued, they will get freed when they finally get out or
 discarded.

Signed-off-by: Xin Long <lucien.xin@gmail.com>
Marcelo Ricardo Leitner <marcelo.leitner@gmail.com>
Signed-off-by: Marcelo Ricardo Leitner <marcelo.leitner@gmail.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
hifive-unleashed-5.1
lucien 2015-12-05 15:19:27 +08:00 committed by David S. Miller
parent 69b5777f2e
commit 8b570dc9f7
1 changed files with 2 additions and 4 deletions
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6
net/sctp/socket.c
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@ -1964,15 +1964,13 @@ static int sctp_sendmsg(struct sock *sk, struct msghdr *msg, size_t msg_len)
* breaks.
*/
err = sctp_primitive_SEND(net, asoc, datamsg);
sctp_datamsg_put(datamsg);
/* Did the lower layer accept the chunk? */
if (err) {
sctp_datamsg_free(datamsg);
if (err)
goto out_free;
}
pr_debug("%s: we sent primitively\n", __func__);
sctp_datamsg_put(datamsg);
err = msg_len;
if (unlikely(wait_connect)) {