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test_bpf: Add test to make conditional jump cross a large number of insns.

On MIPS, conditional branches can only span 32k instructions.  To
exceed this limit in the JIT with the BPF maximum of 4k insns, we need
to choose eBPF insns that expand to more than 8 machine instructions.
Use BPF_LD_ABS as it is quite complex.  This forces the JIT to invert
the sense of the branch to branch around a long jump to the end.

This (somewhat) verifies that the branch inversion logic and target
address calculation of the long jumps are done correctly.

Signed-off-by: David Daney <david.daney@cavium.com>
Acked-by: Daniel Borkmann <daniel@iogearbox.net>
Signed-off-by: David S. Miller <davem@davemloft.net>
hifive-unleashed-5.1
David Daney 2017-06-13 16:49:36 -07:00 committed by David S. Miller
parent e274da1a50
commit b7127cfea0
1 changed files with 32 additions and 0 deletions

View File

@ -435,6 +435,30 @@ loop:
return 0;
}
static int bpf_fill_jump_around_ld_abs(struct bpf_test *self)
{
unsigned int len = BPF_MAXINSNS;
struct bpf_insn *insn;
int i = 0;
insn = kmalloc_array(len, sizeof(*insn), GFP_KERNEL);
if (!insn)
return -ENOMEM;
insn[i++] = BPF_MOV64_REG(R6, R1);
insn[i++] = BPF_LD_ABS(BPF_B, 0);
insn[i] = BPF_JMP_IMM(BPF_JEQ, R0, 10, len - i - 2);
i++;
while (i < len - 1)
insn[i++] = BPF_LD_ABS(BPF_B, 1);
insn[i] = BPF_EXIT_INSN();
self->u.ptr.insns = insn;
self->u.ptr.len = len;
return 0;
}
static int __bpf_fill_stxdw(struct bpf_test *self, int size)
{
unsigned int len = BPF_MAXINSNS;
@ -5044,6 +5068,14 @@ static struct bpf_test tests[] = {
{ { ETH_HLEN, 0xbef } },
.fill_helper = bpf_fill_ld_abs_vlan_push_pop,
},
{
"BPF_MAXINSNS: jump around ld_abs",
{ },
INTERNAL,
{ 10, 11 },
{ { 2, 10 } },
.fill_helper = bpf_fill_jump_around_ld_abs,
},
/*
* LD_IND / LD_ABS on fragmented SKBs
*/