s390: Avoid call to irq_reserve_irqs()
There is no need to mark the lower interrupts as reserved in order to exclude them from dynamic allocation. Provide arch_dynirq_lower_bound() to exclude the lower space. Signed-off-by: Thomas Gleixner <tglx@linutronix.de> Reviewed-by: Grant Likely <grant.likely@linaro.org> Cc: Tony Luck <tony.luck@intel.com> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Martin Schwidefsky <schwidefsky@de.ibm.com> Cc: Heiko Carstens <heiko.carstens@de.ibm.com> Cc: linux390@de.ibm.com Link: http://lkml.kernel.org/r/20140507154339.811205235@linutronix.de Signed-off-by: Thomas Gleixner <tglx@linutronix.de>
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@ -92,7 +92,6 @@ static const struct irq_class irqclass_sub_desc[NR_ARCH_IRQS] = {
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void __init init_IRQ(void)
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{
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irq_reserve_irqs(0, THIN_INTERRUPT);
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init_cio_interrupts();
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init_airq_interrupts();
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init_ext_interrupts();
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@ -151,6 +150,11 @@ out:
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return 0;
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}
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unsigned int arch_dynirq_lower_bound(unsigned int from)
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{
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return from < THIN_INTERRUPT ? THIN_INTERRUPT : from;
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}
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/*
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* Switch to the asynchronous interrupt stack for softirq execution.
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*/
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