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regmap: Do not call regcache_exit from regcache_lzo_init error path 

Calling regcache_exit from regcache_lzo_init is first of all a layering
violation and secondly will cause double frees. regcache_exit will free buffers
allocated by the core, but the core will also free the same buffers when the
cacheops init callback returns an error. Thus we end up with a double free.
Fix this by not calling regcache_exit but only free those buffers which, have
been allocated in this function.

Signed-off-by: Lars-Peter Clausen <lars@metafoo.de>
Acked-by: Dimitris Papastamos <dp@opensource.wolfsonmicro.com>
Signed-off-by: Mark Brown <broonie@opensource.wolfsonmicro.com>
hifive-unleashed-5.1
Lars-Peter Clausen 2011-11-15 13:34:41 +01:00 committed by Mark Brown
parent 462a185c5c
commit c2b1ecd13c
1 changed files with 3 additions and 1 deletions
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4
drivers/base/regmap/regcache-lzo.c
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@ -15,6 +15,8 @@
#include "internal.h"
static int regcache_lzo_exit(struct regmap *map);
struct regcache_lzo_ctx {
void *wmem;
void *dst;
@ -193,7 +195,7 @@ static int regcache_lzo_init(struct regmap *map)
return 0;
err:
regcache_exit(map);
regcache_lzo_exit(map);
return ret;
}