regmap: Do not call regcache_exit from regcache_lzo_init error path
Calling regcache_exit from regcache_lzo_init is first of all a layering violation and secondly will cause double frees. regcache_exit will free buffers allocated by the core, but the core will also free the same buffers when the cacheops init callback returns an error. Thus we end up with a double free. Fix this by not calling regcache_exit but only free those buffers which, have been allocated in this function. Signed-off-by: Lars-Peter Clausen <lars@metafoo.de> Acked-by: Dimitris Papastamos <dp@opensource.wolfsonmicro.com> Signed-off-by: Mark Brown <broonie@opensource.wolfsonmicro.com>
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@ -15,6 +15,8 @@
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#include "internal.h"
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static int regcache_lzo_exit(struct regmap *map);
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struct regcache_lzo_ctx {
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void *wmem;
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void *dst;
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@ -193,7 +195,7 @@ static int regcache_lzo_init(struct regmap *map)
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return 0;
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err:
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regcache_exit(map);
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regcache_lzo_exit(map);
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return ret;
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}
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