regmap: Remove default cache sync implementation
It's not used as all cache types have sync operations so it's just dead code which never gets tested. Signed-off-by: Mark Brown <broonie@opensource.wolfsonmicro.com>
This commit is contained in:
parent
2a14d7d9b7
commit
c3ec23288a
|
@ -254,12 +254,11 @@ EXPORT_SYMBOL_GPL(regcache_write);
|
|||
int regcache_sync(struct regmap *map)
|
||||
{
|
||||
int ret = 0;
|
||||
unsigned int val;
|
||||
unsigned int i;
|
||||
const char *name;
|
||||
unsigned int bypass;
|
||||
|
||||
BUG_ON(!map->cache_ops);
|
||||
BUG_ON(!map->cache_ops || !map->cache_ops->sync);
|
||||
|
||||
mutex_lock(&map->lock);
|
||||
/* Remember the initial bypass state */
|
||||
|
@ -284,24 +283,8 @@ int regcache_sync(struct regmap *map)
|
|||
}
|
||||
map->cache_bypass = 0;
|
||||
|
||||
if (map->cache_ops->sync) {
|
||||
ret = map->cache_ops->sync(map);
|
||||
} else {
|
||||
for (i = 0; i < map->num_reg_defaults; i++) {
|
||||
ret = regcache_read(map, i, &val);
|
||||
if (ret < 0)
|
||||
goto out;
|
||||
map->cache_bypass = 1;
|
||||
ret = _regmap_write(map, i, val);
|
||||
map->cache_bypass = 0;
|
||||
if (ret < 0)
|
||||
goto out;
|
||||
dev_dbg(map->dev, "Synced register %#x, value %#x\n",
|
||||
map->reg_defaults[i].reg,
|
||||
map->reg_defaults[i].def);
|
||||
}
|
||||
ret = map->cache_ops->sync(map);
|
||||
|
||||
}
|
||||
out:
|
||||
trace_regcache_sync(map->dev, name, "stop");
|
||||
/* Restore the bypass state */
|
||||
|
|
Loading…
Reference in a new issue