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x86: make 'constant_test_bit()' take an unsigned bit number 

Ingo noticed that using signed arithmetic seems to confuse the gcc
inliner, and make it potentially decide that it's all too complicated.

(Yeah, yeah, it's a constant. It's always positive. Still..)

Based-on: Ingo Molnar <mingo@elte.hu>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
hifive-unleashed-5.1
Linus Torvalds 2009-01-09 12:49:50 -08:00
parent e245b80c83
commit c4295fbb60
1 changed files with 1 additions and 1 deletions
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2
arch/x86/include/asm/bitops.h
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@ -300,7 +300,7 @@ static inline int test_and_change_bit(int nr, volatile unsigned long *addr)
return oldbit;
}
static inline int constant_test_bit(int nr, const volatile unsigned long *addr)
static inline int constant_test_bit(unsigned int nr, const volatile unsigned long *addr)
{
return ((1UL << (nr % BITS_PER_LONG)) &
(((unsigned long *)addr)[nr / BITS_PER_LONG])) != 0;