kconfig: Don't write invisible choice values
This makes it so "make oldconfig" really prompts for any choice where options that previously weren't visible just became so. Previously one would have to remember to go over all choice values and check whether some that previously couldn't be selected now can be. Signed-off-by: Jan Beulich <jbeulich@novell.com> Signed-off-by: Michal Marek <mmarek@suse.cz>
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@ -232,13 +232,15 @@ static struct symbol *sym_calc_choice(struct symbol *sym)
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struct property *prop;
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struct expr *e;
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/* first calculate all choice values' visibilities */
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prop = sym_get_choice_prop(sym);
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expr_list_for_each_sym(prop->expr, e, def_sym)
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sym_calc_visibility(def_sym);
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/* is the user choice visible? */
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def_sym = sym->def[S_DEF_USER].val;
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if (def_sym) {
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sym_calc_visibility(def_sym);
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if (def_sym->visible != no)
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if (def_sym && def_sym->visible != no)
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return def_sym;
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}
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/* any of the defaults visible? */
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for_all_defaults(sym, prop) {
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@ -246,18 +248,15 @@ static struct symbol *sym_calc_choice(struct symbol *sym)
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if (prop->visible.tri == no)
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continue;
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def_sym = prop_get_symbol(prop);
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sym_calc_visibility(def_sym);
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if (def_sym->visible != no)
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return def_sym;
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}
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/* just get the first visible value */
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prop = sym_get_choice_prop(sym);
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expr_list_for_each_sym(prop->expr, e, def_sym) {
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sym_calc_visibility(def_sym);
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expr_list_for_each_sym(prop->expr, e, def_sym)
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if (def_sym->visible != no)
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return def_sym;
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}
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/* no choice? reset tristate value */
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sym->curr.tri = no;
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@ -383,12 +382,13 @@ void sym_calc_value(struct symbol *sym)
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if (sym_is_choice(sym)) {
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struct symbol *choice_sym;
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int flags = sym->flags & (SYMBOL_CHANGED | SYMBOL_WRITE);
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prop = sym_get_choice_prop(sym);
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expr_list_for_each_sym(prop->expr, e, choice_sym) {
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choice_sym->flags |= flags;
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if (flags & SYMBOL_CHANGED)
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if ((sym->flags & SYMBOL_WRITE) &&
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choice_sym->visible != no)
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choice_sym->flags |= SYMBOL_WRITE;
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if (sym->flags & SYMBOL_CHANGED)
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sym_set_changed(choice_sym);
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}
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}
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