redonkable
/
remarkable-linux
1
0
Fork 0
Code Releases Activity

bpf: fix misleading comment in bpf_convert_filter 

Comment says "User BPF's register A is mapped to our BPF register 6",
which is actually wrong as the mapping is on register 0. This can
already be inferred from the code itself. So just remove it before
someone makes assumptions based on that. Only code tells truth. ;)

Signed-off-by: Daniel Borkmann <daniel@iogearbox.net>
Acked-by: Alexei Starovoitov <ast@kernel.org>
Signed-off-by: David S. Miller <davem@davemloft.net>
steinar/wifi_calib_4_9_kernel
Daniel Borkmann 2015-12-17 23:51:55 +01:00 committed by David S. Miller
parent 8b614aebec
commit 23bf88078a
1 changed files with 0 additions and 6 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

6
net/core/filter.c
View File

@ -348,12 +348,6 @@ static bool convert_bpf_extensions(struct sock_filter *fp,
* jump offsets, 2nd pass remapping:
* new_prog = kmalloc(sizeof(struct bpf_insn) * new_len);
* bpf_convert_filter(old_prog, old_len, new_prog, &new_len);
*
* User BPF's register A is mapped to our BPF register 6, user BPF
* register X is mapped to BPF register 7; frame pointer is always
* register 10; Context 'void *ctx' is stored in register 1, that is,
* for socket filters: ctx == 'struct sk_buff *', for seccomp:
* ctx == 'struct seccomp_data *'.
*/
static int bpf_convert_filter(struct sock_filter *prog, int len,
struct bpf_insn *new_prog, int *new_len)