dynamic debug: resurrect old pr_debug() semantics as pr_devel()
pr_debug() used to produce zero code unless DEBUG was #defined. This is now no longer the case in practice[1]. There are places where it's useful to have debugging printks, but we don't want them to generate any code in production kernels. So add a new macro, pr_devel(), for _devel_opment, to provide the old semantics, ie. if the programmer doesn't explicitly enable debugging, no code is produced. [1]: You can turn CONFIG_DYNAMIC_DEBUG off, but it's enabled in at least one distro kernel, so it's not really a solution. Signed-off-by: Michael Ellerman <michael@ellerman.id.au> Cc: Jason Baron <jbaron@redhat.com> Cc: Greg Banks <gnb@sgi.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
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@ -377,6 +377,15 @@ static inline char *pack_hex_byte(char *buf, u8 byte)
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#define pr_cont(fmt, ...) \
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printk(KERN_CONT fmt, ##__VA_ARGS__)
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/* pr_devel() should produce zero code unless DEBUG is defined */
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#ifdef DEBUG
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#define pr_devel(fmt, ...) \
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printk(KERN_DEBUG pr_fmt(fmt), ##__VA_ARGS__)
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#else
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#define pr_devel(fmt, ...) \
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({ if (0) printk(KERN_DEBUG pr_fmt(fmt), ##__VA_ARGS__); 0; })
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#endif
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/* If you are writing a driver, please use dev_dbg instead */
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#if defined(DEBUG)
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#define pr_debug(fmt, ...) \
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