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f2fs: allocate remained free segments in the LFS mode

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This patch adds a new condition that allocates free segments in the current
active section even if SSR is needed.
Otherwise, f2fs cannot allocate remained free segments in the section since
SSR finds dirty segments only.

Reviewed-by: Namjae Jeon <namjae.jeon@samsung.com>
Signed-off-by: Jaegeuk Kim <jaegeuk.kim@samsung.com>
This commit is contained in:
Jaegeuk Kim 2013-03-31 13:58:51 +09:00
parent 4ebefc4443
commit 60374688a1
1 changed files with 13 additions and 0 deletions
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13
fs/f2fs/segment.c
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@ -347,6 +347,17 @@ next:
return NULL_SEGNO;
}
static int is_next_segment_free(struct f2fs_sb_info *sbi, int type)
{
struct curseg_info *curseg = CURSEG_I(sbi, type);
unsigned int segno = curseg->segno;
struct free_segmap_info *free_i = FREE_I(sbi);
if (segno + 1 < TOTAL_SEGS(sbi) && (segno + 1) % sbi->segs_per_sec)
return !test_bit(segno + 1, free_i->free_segmap);
return 0;
}
/*
* Find a new segment from the free segments bitmap to right order
* This function should be returned with success, otherwise BUG
@ -580,6 +591,8 @@ static void allocate_segment_by_default(struct f2fs_sb_info *sbi,
change_curseg(sbi, type, false);
else if (type == CURSEG_WARM_NODE)
new_curseg(sbi, type, false);
else if (curseg->alloc_type == LFS && is_next_segment_free(sbi, type))
new_curseg(sbi, type, false);
else if (need_SSR(sbi) && get_ssr_segment(sbi, type))
change_curseg(sbi, type, true);
else