PCI: Create alloc_pci_dev(), the one true way to create a struct pci_dev

There are currently several places in the kernel where we kmalloc()
a struct pci_dev and start initialising it. It'd be preferable to
have an allocator so we can ensure the pci_dev is correctly initialised
in one place.

Signed-off-by: Michael Ellerman <michael@ellerman.id.au>
Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
This commit is contained in:
Michael Ellerman 2007-04-05 17:19:08 +10:00 committed by Greg Kroah-Hartman
parent c9953a73e9
commit 65891215e6
2 changed files with 17 additions and 0 deletions

View file

@ -846,6 +846,21 @@ static void pci_release_bus_bridge_dev(struct device *dev)
kfree(dev);
}
struct pci_dev *alloc_pci_dev(void)
{
struct pci_dev *dev;
dev = kzalloc(sizeof(struct pci_dev), GFP_KERNEL);
if (!dev)
return NULL;
INIT_LIST_HEAD(&dev->global_list);
INIT_LIST_HEAD(&dev->bus_list);
return dev;
}
EXPORT_SYMBOL(alloc_pci_dev);
/*
* Read the config data for a PCI device, sanity-check it
* and fill in the dev structure...

View file

@ -193,6 +193,8 @@ struct pci_dev {
#endif
};
extern struct pci_dev *alloc_pci_dev(void);
#define pci_dev_g(n) list_entry(n, struct pci_dev, global_list)
#define pci_dev_b(n) list_entry(n, struct pci_dev, bus_list)
#define to_pci_dev(n) container_of(n, struct pci_dev, dev)