debugfs: Remove misleading comments.

Just mention which error will be returned if debugfs is disabled. Callers
should be able to figure out themselves what they need to check.

Signed-off-by: Cornelia Huck <cornelia.huck@de.ibm.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
This commit is contained in:
Cornelia Huck 2007-02-14 07:57:47 +01:00 committed by Greg Kroah-Hartman
parent 66f5496393
commit 873760fbf4

View file

@ -212,9 +212,7 @@ static int debugfs_create_by_name(const char *name, mode_t mode,
* you are responsible here.) If an error occurs, %NULL will be returned.
*
* If debugfs is not enabled in the kernel, the value -%ENODEV will be
* returned. It is not wise to check for this value, but rather, check for
* %NULL or !%NULL instead as to eliminate the need for #ifdef in the calling
* code.
* returned.
*/
struct dentry *debugfs_create_file(const char *name, mode_t mode,
struct dentry *parent, void *data,
@ -264,9 +262,7 @@ EXPORT_SYMBOL_GPL(debugfs_create_file);
* you are responsible here.) If an error occurs, %NULL will be returned.
*
* If debugfs is not enabled in the kernel, the value -%ENODEV will be
* returned. It is not wise to check for this value, but rather, check for
* %NULL or !%NULL instead as to eliminate the need for #ifdef in the calling
* code.
* returned.
*/
struct dentry *debugfs_create_dir(const char *name, struct dentry *parent)
{
@ -297,9 +293,7 @@ EXPORT_SYMBOL_GPL(debugfs_create_dir);
* returned.
*
* If debugfs is not enabled in the kernel, the value -%ENODEV will be
* returned. It is not wise to check for this value, but rather, check for
* %NULL or !%NULL instead as to eliminate the need for #ifdef in the calling
* code.
* returned.
*/
struct dentry *debugfs_create_symlink(const char *name, struct dentry *parent,
const char *target)