debugfs: Remove misleading comments.
Just mention which error will be returned if debugfs is disabled. Callers should be able to figure out themselves what they need to check. Signed-off-by: Cornelia Huck <cornelia.huck@de.ibm.com> Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
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@ -212,9 +212,7 @@ static int debugfs_create_by_name(const char *name, mode_t mode,
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* you are responsible here.) If an error occurs, %NULL will be returned.
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*
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* If debugfs is not enabled in the kernel, the value -%ENODEV will be
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* returned. It is not wise to check for this value, but rather, check for
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* %NULL or !%NULL instead as to eliminate the need for #ifdef in the calling
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* code.
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* returned.
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*/
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struct dentry *debugfs_create_file(const char *name, mode_t mode,
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struct dentry *parent, void *data,
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@ -264,9 +262,7 @@ EXPORT_SYMBOL_GPL(debugfs_create_file);
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* you are responsible here.) If an error occurs, %NULL will be returned.
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*
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* If debugfs is not enabled in the kernel, the value -%ENODEV will be
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* returned. It is not wise to check for this value, but rather, check for
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* %NULL or !%NULL instead as to eliminate the need for #ifdef in the calling
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* code.
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* returned.
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*/
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struct dentry *debugfs_create_dir(const char *name, struct dentry *parent)
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{
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@ -297,9 +293,7 @@ EXPORT_SYMBOL_GPL(debugfs_create_dir);
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* returned.
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*
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* If debugfs is not enabled in the kernel, the value -%ENODEV will be
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* returned. It is not wise to check for this value, but rather, check for
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* %NULL or !%NULL instead as to eliminate the need for #ifdef in the calling
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* code.
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* returned.
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*/
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struct dentry *debugfs_create_symlink(const char *name, struct dentry *parent,
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const char *target)
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