[IA64] bte_unaligned_copy() transfers one extra cache line.

When called to do a transfer that has a start offset within the cache
line which is uneven between source and destination and a length which
terminates the source of the copy exactly on a cache line, one extra
line gets copied into a temporary buffer.  This is normally not an issue
since the buffer is a kernel buffer and only the requested information
gets copied into the user buffer.

The problem arises when the source ends at the very last physical page
of memory.  That last cache line does not exist and results in the SHUB
chip raising an MCA.

Signed-off-by: Robin Holt <holt@sgi.com>
Signed-off-by: Dean Nelson <dcn@sgi.com>
Signed-off-by: Tony Luck <tony.luck@intel.com>
This commit is contained in:
Robin Holt 2006-11-14 20:50:59 -06:00 committed by Tony Luck
parent 45c9953325
commit cbf093e8c7

View file

@ -381,14 +381,13 @@ bte_result_t bte_unaligned_copy(u64 src, u64 dest, u64 len, u64 mode)
* bcopy to the destination.
*/
/* Add the leader from source */
headBteLen = len + (src & L1_CACHE_MASK);
/* Add the trailing bytes from footer. */
headBteLen += L1_CACHE_BYTES - (headBteLen & L1_CACHE_MASK);
headBteSource = src & ~L1_CACHE_MASK;
headBcopySrcOffset = src & L1_CACHE_MASK;
headBcopyDest = dest;
headBcopyLen = len;
headBteSource = src - headBcopySrcOffset;
/* Add the leading and trailing bytes from source */
headBteLen = L1_CACHE_ALIGN(len + headBcopySrcOffset);
}
if (headBcopyLen > 0) {