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[S390] s390: clear high-order bits of registers after sam64

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When the kernel is IPLed without the CLEAR option and switches
to 64-bit, the high-order half of the registers might contain
random values.  This can cause addressing exceptions and the
kernel enters an interrupt loop.

Initialize the high-order half of the general purpose registers
with zeros after switching to 64-bit mode.

Cc: <stable@kernel.org>
Signed-off-by: Hendrik Brueckner <brueckner@linux.vnet.ibm.com>
Signed-off-by: Martin Schwidefsky <schwidefsky@de.ibm.com>
This commit is contained in:
Hendrik Brueckner 2009-12-07 12:44:42 +01:00 committed by Martin Schwidefsky
parent 6ec22f9b03
commit cf87b7439e
1 changed files with 3 additions and 0 deletions
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3
arch/s390/kernel/head64.S
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@ -83,6 +83,8 @@ startup_continue:
slr %r0,%r0 # set cpuid to zero
sigp %r1,%r0,0x12 # switch to esame mode
sam64 # switch to 64 bit mode
llgfr %r13,%r13 # clear high-order half of base reg
lmh %r0,%r15,.Lzero64-.LPG1(%r13) # clear high-order half
lctlg %c0,%c15,.Lctl-.LPG1(%r13) # load control registers
lg %r12,.Lparmaddr-.LPG1(%r13) # pointer to parameter area
# move IPL device to lowcore
@ -127,6 +129,7 @@ startup_continue:
.L4malign:.quad 0xffffffffffc00000
.Lscan2g:.quad 0x80000000 + 0x20000 - 8 # 2GB + 128K - 8
.Lnop: .long 0x07000700
.Lzero64:.fill 16,4,0x0
#ifdef CONFIG_ZFCPDUMP
.Lcurrent_cpu:
.long 0x0